Basic Statistics and Number Series: Methods and Worked Examples
Mean, median, mode and range for ungrouped data, simple probability with dice and balls, and the common patterns in number-series and analogy questions.
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Measures of central tendency
For ungrouped data (a plain list of values) three averages are examined.
| Measure | How to find it |
|---|---|
| Mean | Sum of all values ÷ number of values |
| Median | Middle value after arranging the data in order |
| Mode | Value that occurs most often |
- Median position for n values in order: the (n + 1)/2 th value. If n is odd this is a single value; if n is even, take the mean of the two middle values.
- A data set can have one mode, two modes (bimodal) or no mode.
- From the mean: Sum = Mean × n. This is used to find a missing value or to adjust for a value added or removed.
Range
Range = Largest value - Smallest value. It is the simplest measure of spread.
Simple probability
When all outcomes are equally likely:
P(E) = Number of favourable outcomes ÷ Total number of possible outcomes
- A probability lies between 0 and 1.
- P(not E) = 1 - P(E).
- One fair die has 6 outcomes; two dice have 6 × 6 = 36 ordered outcomes; two coins have 4.
- The prime numbers on a die are 2, 3 and 5. The number 1 is not prime.
Number series
Find the rule that links each term to the next. Check the patterns in this order:
- Constant difference (arithmetic): 7, 11, 15, 19 adds 4 each time.
- Constant ratio (geometric): 3, 6, 12, 24 doubles each time.
- Growing differences: 2, 6, 12, 20, 30 has differences 4, 6, 8, 10. Here the n-th term is n × (n + 1).
- Mixed operation: 5, 11, 23, 47 is "multiply by 2 and add 1".
- Squares and cubes: 1, 4, 9, 16 or 1, 8, 27, 64, sometimes with 1 added or subtracted.
Number analogy
In an analogy such as 3 : 10 the second number is made from the first by a rule (here square and add 1, since 3² + 1 = 10). Test the rule on every given pair before applying it to the unknown.
Worked examples
- Mean, median and range. Data: 6, 9, 12, 15, 23. Mean = 65 ÷ 5 = 13. Median = third value = 12. Range = 23 - 6 = 17.
- Median with an even count. Data: 23, 15, 31, 18, 27, 12, 35, 20. In order: 12, 15, 18, 20, 23, 27, 31, 35. Median = (20 + 23) ÷ 2 = 21.5.
- Probability. A bag has 5 red, 4 blue and 3 green balls. P(blue) = 4/12 = 1/3, so P(not blue) = 1 - 1/3 = 2/3. Directly, 8 non-blue balls out of 12 = 2/3.
- Two dice. A sum of 8 arises from (2,6), (3,5), (4,4), (5,3) and (6,2): 5 outcomes out of 36, so the probability is 5/36.
- Series. 5, 11, 23, 47, 95, ? Each term is double the previous term plus 1, so the next is 95 × 2 + 1 = 191. The differences 6, 12, 24, 48 also double, giving 95 + 96 = 191.
Exam pointers
- Always arrange the data in ascending order before picking the median.
- With an even number of values the median may not be one of the data values.
- Mean, median and mode are usually all placed among the options, so be sure which one is asked.
- For two dice count ordered pairs: (3,5) and (5,3) are different outcomes but (4,4) occurs once.
- Use the complement, 1 - P(E), for "not" and "at least one" questions.
- In a series, confirm the rule with a second method such as the differences before marking the answer.
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Sources
- OpenStax Contemporary Mathematics, 8.3 Mean, Median and Mode
- OpenStax Contemporary Mathematics, 8.4 Range and Standard Deviation
- OpenStax Contemporary Mathematics, 7.5 Basic Concepts of Probability
- OpenStax Intermediate Algebra 2e, 12.1 Sequences
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